Problems on Percentages

Problems on Percentages

1. A’s income is 20% more than that of B while B’s income is 20% less than that of C. Whose income is the highest amongst all?
 Sol : Let the income of C be Rs. 100/-
            So, The income of B is Rs. 80/-
            A’s income is 20% more than B = (120/100) X 80 = Rs. 96/-
           So, obviously C’s income is Highest

2. A’s income exceeds that of B’s by Rs.600 while B’s income is 20% less than that of C’s. If total income of all of them put together is Rs. 3.850, what is the income of C ?

      Sol : Let the income of C be Rs. X
              B’s income is 20% less than C’s

 

              So, B’s income is 80% of  X  = 4 X  / 5

 

              So, A’s income is (4 X /5) + 600

 

                   =>  ((4 X /5)+600) + (4 X /5) +  X  = 3,850

 

                    => (8 X  / 5) +  X  = 3,250

 

                       =>  13  X  = 5 x 3,250

 

                                   X  = (5 x 3,250) / 13 = Rs. 1,250

3. Shivani spends 15% of her salary on Shopping, 20% on House – Rent, 50 % on Food and the remaining on Education of Her children. If education costs her Rs 3000, how much does she spend on House – Rent ? 

         Sol :  Let the salary of Shivani is Rs. 100
                   So, amount spent on Education = 100 – ( 15 + 20 + 50) = Rs. 15
                    But, her expences towards education is Rs. 3000
                     So, 15% of salary = (3000 x 100) / 15  = Rs. 20,000
                     She spent 20% of her salary on house rent
                              So, 20% of 20,000 = Rs. 4000/-
4. In a class, 30% students passed in Maths, 50% students passed in English and 10% students passed in Both. What per cent of students failed in both of these subjects?

        Sol : Let the number of total students = 100
                 So, Number of students passed in Maths = 30
                        Number of students passed in English = 50
                        Number of students passed in Maths and English = 10
                   So, total number of students passed = (30 + 50 – 10) = 70
                         Number of students failed = 30
                      So,     Percentage of Students failed = 30 %
5. A trader announced 10% reduction in the unit price of an article. As a result, the sales volume went up by 10%. What was the net effect on the sales revenue?
          Sol : Let the unit price be Rs. 10/-
                   Let the number of articles sold = 10
                    So, the sales revenue = 10 x 10 = Rs. 100
                    The trader has reduced the unit price by 10%
                    So, Reduced price = 90% of Rs 10 = Rs. 9 /-
                              and, increase in the sales volume = 10%
                                          = 110% of 10 = 11
                          So, The net effect = 9 x 11 = Rs. 99
                              The sales revenue has come down by Re. 1/-
                        So, the sales revenue has come down by 1%
        Note : There is a short cut for these type of problems.
                    If price is reduced by X% and sales increase by Y%, the total effect on sales revenue :
               =      increased % value – Decreased % value = (Increased % value x Decreased % value) / 100
                The effect on revenue is increased or decreased according to the positive or negative sign otained
                       =  10 – 10 – ((10 x 10) / 10)) = 0 – 1 = -1

The sign obtained is negative. Thus, the total revenue decreases by 1%

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