Percentage Type 3 Shortcut Tricks
We all know that the most important thing in competitive exams is Mathematics. That doesn’t mean that other topics are less important. You can get a good score only if you get a good score in math section. A good score comes with practice and practice. All you need to do is to do math problems correctly within time, and you can do this only by using shortcut tricks. But it doesn’t mean that you can’t do math problems without using any shortcut tricks. You may have that potential to do maths within time without using any shortcut tricks. But so many other people may not do the same. For those we prepared this percentage shortcut tricks. We try our level best to put together all types of shortcut methods here. But if you see any tricks are missing from the list then please inform us. Your little help will help others.
Example 1:
Bijoy invest his money from his saving in different way that is he invest 30% on buying books, 10% on nutrition, 15% on wages and 22% on purchase a bike and after that all expenditure he saved 4600. Find the how much he spent on bike.
Answer :
Let the total income of Bijoy x. then total expenditure from income X x ( 30% + 10% + 15% + 22% ) = X x 77% = Total savings = X x 23%
X = 4600 x 100 / 23 = 20000 and expenditure on Bike = 22% so, 20000 x 22 / 100 = 4400.
Shortcut Tricks
The total income as 100% so, ( 100% – 30% + 10% + 15% + 22% ) = 77% and now ( 100% – 77% ) = 23%
Bike Expenditure is now 4600 x 22 / 23 = 4400.
Example 2:
If X is 80% of Y, then What percent of X is Y ?
Solution :
X = 80 / 100 x Y
X = 4 / 5 x Y
Y / X = 5 / 4.
Example 3 :
54.5% of 600 + 30.5% of 1800 = (?) + 147
Answer :
327 + 549 = (?) + 147
(?) = 729
? = 27.
Example 4 :
What is 25% of 25% equal to ?
Answer :
25% of 25% = 25 / 100 x 25 / 100 = 1 / 16 = 0.0625.
Example 5:
Subtracting 60% of a number from the number, We get the result as 20. The number is :
Solution :
Let the number is x, then ,
x – 60 / 100x = 20
x – 3 / 5 = 20
2x / 5 = 20
x = 20 x 5 / 2 = 50.
Example 6 :
In Mumbai due to reduction by 10% in the price of sugar, a person is able to buy 2 kg more for Rs. 280 . Find the reduced rate/kg of sugar ?
Answer :
10% of 280 is due to reduction of price in sugar
Rs. 28 = 2 kg
Rs. 14 = 1 kg.
Example 7:
In an party election between two candidates, one got 45% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was
Answer :
Number of valid votes
= 80% of 7500
= ( 80 / 100 ) x 7500 = 6000.
one got 45% of the votes
So other Valid votes polled by other candidate = 55% of 6000
= ( 55 / 100 ) × 6000 = 3300.
The number of valid votes that the other candidates got is 3300.
Example 8 :
If the price of diesel is increased by 25%, by how much percent a car owner must reduce his consumption in order to maintain the same budget ?
Answer :
25% = 25 x 100 / 125 = 20% less
20% a car owner must reduce his consumption in order to maintain the same budget.
Example 9 :
If the sugar price is increased by 8%, then by how much percent should a housewife reduce her consumption of sugar, to have no extra expenditure ?
Answer :
Less% = 8 x 100 / 108
= 800 / 108
= 7.40%
Example 10 :
In an general election a candidate who gets 64% of the total votes and wins by 476 votes. What is the total number of votes polled ?
Answer :
64% – ( 100% – 64% )
= 64% – 36%
= 28% = 476
= 476 x 100 / 28 = 1700.