### Frustum or right Circular cone

Frustum of a right circular cone is that portion of right circular cone included between the base and a section parallel to the base not passing through the vertex.

### Properties of Frustum of Right Circular Cone:

- The altitude of a frustum of a right circular cone is the perpendicular distance between the two bases. It is denoted by h.
- All elements of a frustum of a right circular cone are equal. It is denoted by L.

### Curved surface area of a frustum :

C.S.A. of a frustum = π(R + r)l sq. units

Where,\( l=\sqrt {h^2 + (R-r)^2} \)

### Example:

The slant height of a frustum of a cone is 5 cm and the radii of its ends are 4 cm and 1 cm. Find its curved surface area.

### Solution:

Given that, l= 5 cm, R = 4 cm, r = 1 cm

Now, C.S.A. of the frustum = π (R + r) l sq. units

Therefore, C.S.A. = 78.57 cm^{2}

### Total surface area of a frustum:

T.S.A. of a frustum = π(R + r)l + πR^{2} + πr ^{2} sq. units

Where, \( l=\sqrt {h^2 + (R-r)^2} \)

### Example:

An industrial metallic bucket is in the shape of the frustum of a right circular cone whose top and bottom diameters are 10 m and 4 m and whose height is 4 m. Find the total surface area of the bucket.

### Solution:

Given that, diameter of the top =10 m; radius of the top R = 5 m.

diameter of the bottom = 4 m; radius of the bottom r = 2 m, height h= 4 m

T.S.A. = 201.14 m^{2}

### Volume of a frustum:

V = (πh/3)(R^{2}+Rr+r^{2})

### Example:

Find the volume of a frustum of a right circular cone with height 20, lower base radius 34 and top radius 19.

### Solution:

Given.

h = 20, R = 34, r = 19

V =( (π×20)/3)(34^{2}+34×19+19^{2})

V = 14420 π cubic units