## Average Methods Example 6

The result obtained by adding several quantities together and then dividing this total by the number of quantities is called Average. This is the basic theory of average which applied in question to obtain answers here is Average Methods of example 5 and shortcut tricks in different form of examples.

This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.

**Example 1:**

The average monthly income of **A and B is Rs.6040.** The monthly average income of **B and C is Rs.7500** and monthly average income of** A and C is Rs. 6500. **Find the** income of A in a monthly income** ?

**Answer:**

**Step 1:** here is ABC given respectively monthly income, hence we need to find both income.

( A + B ) = ( 6040 x 2 ) = **12080,** ( B + C ) =( 7500 x 2 ) = **15000,** ( C + A ) = ( 6500 x 2 ) = **13000**

**Step 2: **If we add 3 income 2( A + B + C ) = 2 x ( 12080 + 15000 + 13000 ) = **40080 **or A + B + C = 40080 / 2 =** 20040.**

**Step 3:** So we get the income of A Subtract income of ( A + B + C ) – ( B + C ) = (20040 – 15000 ) = **5040.5**

**Example 2:**

The average of Five numbers is 62. The average of the second and the third number is 45. The average of the first and the fifth number is 66. What would be the fourth number ?

**Answer :**

Average of Five numbers is = 62 x 5 = 310

Average of second and third number = 45 x 2 = 90

Average of first and fourth number = 66 x 2 = 132

( 132 + 90 ) = 222

The fourth number is ( 310 – 222 ) = 88

**Example 3:**

The average of 5 numbers is 4.5. If average of two number is 3.5 and that of another two numbers is 3.7, then what is the last number?

**Answer :**

2 x 3.5 = 7

2 x 3.7 = 7.4

5 x 4.5 = 22.5

( 22.5 – 7.4 + 7 ) = 8.1

So the last number is 8.1.

**Example 4:**

The average of 4 consecutive odd numbers P , Q , R , S is 66. What would be the product of P and S?

**Answer :**

Average is 66

P Q R S

63 64 65 66 67 68 69

Product of ( P x S ) = ( 63 x 69 ) = 4347.

**Example 5:**

In a school of class x after replacing an old student by new student, it was found that the average age of eight student of a class x is the same as it was 5 years ago. What is the differences between the ages of the replaced and new student ?

**Answer :** Age decreased = ( 8 x 5 ) = 40 years.

So the required age difference is = 40 years.

**Example 6:**

If the average of 8 numbers is 2.85. If the two number average is 2.3 and other two number average is 3.9, then Find the average of other two numbers ?

**Answer:** 22.8 – ( 9.2 + 7.8) / 2 =** 2.9.**

the average of other two numbers 2.9.