Average Methods Example 1
In this average methods Example 1 we discuss some examples which help your better understanding in average chapter which came in most competitive exams.This is the basic theory of average which applied in question to obtain answers here is Average Methods of example 1 in different form of examples.
This type of problem are given in Quantitative Aptitude which is a very essential paper in banking exam. Under below given some more example for your better practice.
Example 1 :
In a School 8 student average weight is increased by 3.5 kg, when new student comes in place of one of them than weight become 55 kg, what would be the weight of the new student ?
Answer :
Step 1: At first we find the total weight increased So, ( 8 X 3.5 )kg = 28 kg.
Step 2: Now the weight of new Student is = ( 55 + 28 )kg = 83 kg.
So, the weight of the new student is 83 kg.
Example 2:
The Average weight 3 girls A, B, and C is 55 kg, While the average weight of three boys B, D, and E is 57 kg. What is the average weight of A, B, C, D, E ?
Answer :
Step 1: At First we find 3 girls total weight ( A + B + C ) = ( 55 X 3 ) = 165 kg. and Total 3 boys weight of ( B + D + E ) = ( 57 x 3 ) = 171.
Step 2: Adding both weight of ( A + 2 B + C + D + E ) = ( 165 + 171 ) = 336 kg.
Note: So, to find the average weight of A B C D and E, we duty to know B’s weight, which is not given. So the data is inadequate.
Example 3:
There are two section X and Y of a College, consisting of 36 and 44 students respectively. if the average weight of section X is 40 Kg and that of section Y is 35 Kg. Find the average weight of the whole College (in Kg) ?
Answer:
Step 1: At first the total ( X + Y ) college students are ( 36 + 44 ) = 80.
Step 2: college X total student weight and college Y total student weight is ( 36 x 40 + 44 x 35 ) = 2980
Average weight of the whole college is = 2980 / 80 = 37.25.
Example 4 :
Find the average of all the numbers between 6 and 34 which are divisible by 5.
Answer:
Step 1: 10 + 15 + 20 + 25 + 30 which are divisible by 5 in between 6 and 34
So average of number is 10 + 15 + 20 + 25 + 30 / 5 = 100 / 5 = 20.
Example 5:
Divya obtain 56, 75, 78, 86 and 88 marks out of 100 in Physics, Life Science, Mathematics, Biology, and Computer. What are her average marks ?
Answer :
Step 1: Average of all subject marks 56 + 75 + 78 + 86 + 88 / 5
=383 / 5 = 76.6.
Example 6:
In an examination it is required to get 34% of the aggregate marks to pass. A student gets 270 marks and is declared failed by 7% marks. What are the maximum aggregate marks a student can get ?
Answer :
Step 1: 34% = 270 + 7%
Step 2: 27% = 270
Step 3: 100% = 270 x 100 / 27 = 1000 marks.