Arithmetic Progression Class 10 Maths Formulas

Arithmetic Progression Class 10 Maths Formulas

For those looking for help on Arithmetic Progression Class 10 Math Concepts can find all of them here provided in a comprehensive manner. To make it easy for you we have jotted the Class 10 Arithmetic Progression Maths Formulae List all at one place. You can find Formulas for all the topics lying within the Arithmetic Progression Class 10 Arithmetic Progression in detail and get a good grip on them. Revise the entire concepts in a smart way taking help of the Maths Formulas for Class 10 Arithmetic Progression.

Maths Formulas for Class 10 Arithmetic Progression

The List of Important Formulas for Class 10 Arithmetic Progression is provided on this page. We have everything covered right from basic to advanced concepts in Arithmetic Progression. Make the most out of the Maths Formulas for Class 10 prepared by subject experts and take your preparation to the next level. Access the Formula Sheet of Arithmetic Progression Class 10 covering numerous concepts and use them to solve your Problems effortlessly.

We have observed many things in our daily life, follow a certain pattern.
(a) 1, 4, 7, 10, 13, 16, …….
(b) 15, 10, 5, 0, -5, -10,………….
(c) 1,\(\frac{1}{2}\),0,\(-\frac{1}{2}\)………………
These patterns are generally known as sequence. Two such sequences are arithmetic and geometric sequences. Let us investigate the Arithmetic sequence.

1. Sequence: A sequence is a ordered list of numbers.
Terms: The various numbers occurring in a sequence are called its terms. Terms of sequence are denoted by a1 a2, a3, …………… an.

2. Arithmetic Progression: An arithmetic progression is a sequence of numbers such that the difference between the consecutive terms are equal.

3. Common difference: The difference between two consecutive terms of an arithmetic progression is called common difference.
d = a2 – a1
d = a3 – a2
d = a4 – a3
……………..
……………..
d = an – an-1

4. Finite Arithmetic Progression: A sequence which has finite or definite number of terms is called finite sequence.
Example, (1, 3, 5, 7, 9)… which has 5 terms.

5. Infinite Arithmetic Progression: A sequence which has indefinite or infinite number of terms is called infinite arithmetic progression.
Example, 1, 2, 3, 4, 5, …

In general, arithmetic progression can be written as a, a + d, a + 2d, where a is the first term and d is called the common difference i.e. difference between two consecutive terms.

6. General form of an AP: Let a be the first term and d is the common difference then the AP is

Here
a1 = a (we take) (a is first term of AP)
a2 = a1 + d = a + d
a3 = a2 + d = a + d + d = a + 2d
a4 = a3+ d = a + 2d + d = a + 3d
…………….
……………
an = a + (n – 1) d
i.e. AP is a, a + d, a + 2d, a + 3d,………… , a + (n – 1)d.
nth term of AP = a + (n -1)d
Note: Common difference of AP can be positive, negative or zero.

1. nth term or General term of an AP
nth term of an AP = a + (n – 1) d where
a → first term of the AP
n → number of terms
d→common difference of an AP.

2. nth term of an AP from the end: Let us consider an AP where first term a and common difference is If m is number of terms in the AP. then
nth term from the end = [m – n + 1]th term from the beginning.
nth term from the end = a + (m-n +1 – 1)d – a + (m – n) d
It l is the last term of the AP, then nth term from the end is the nth term of an AP where first term is l and common difference is – d
nth term from the end – 1 + (n – 1) (-d)
= 1 – (n – 1) d

Sum of first n terms of an AP
Let Sn denote the sum of first n terms of an AP
Sn = a + a + d + a + 2d + a + 3d …. + a + (n – 1)d ……….. (1)
Rewriting the terms in reverse order.
Sn = a + (n – 1) + a + (n – 2)d + a + (n-3)d + ………….+a ……… (2)
Adding equations (1) and (2)
2Sn = [2a + (n – 1)d] + [2a + (n-1)d] + … + [2a + (n – 1)d]
2Sn = n[2a + (n – 1)d]
Sn=\(\frac{n}{2}\)[2a+(n-1)d]
We can Write
Sn=\(\frac{n}{2}\)[a+a+(n-1)d] [l=a+(n-1)d]
Sn=\(\frac{n}{2}\)[a+l]

Note:
(i) The Tith term of an AP = Sn – Sn-1 or an = Sn+1 – Sn
Sum of first n positive integer
\(S_{n}=\frac{n(n+1)}{2}\)
(iii) Sum of n odd positive integer = n2
(iv) Sum of n even positive integer = n(n + 1)

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